What is the critical (8x^2-24x)/(3(x+1)^{1/3)} ?

The critical (8x^2-24x)/(3(x+1)^{1/3)} is x=-3/(sqrt(5)),x= 3/(sqrt(5))

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critical (8x^2-24x)/(3(x+1)^{1/3)}

critical points

\frac{8 x ^{2} - 24 x}{3 ( x + 1 ) ^{\frac{1}{3}}}

x = - \frac{3}{5}, x = \frac{3}{5}

Solution steps

\frac{8 x ^{2} - 24 x}{3 ( x + 1 ) ^{\frac{1}{3}}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{5}, x = \frac{3}{5}, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{8 x ^{2} - 24 x}{3 ( x + 1 ) ^{\frac{1}{3}}} : x < - 1 or x > - 1

\frac{8 x ^{2} - 24 x}{3 ( x + 1 ) ^{\frac{1}{3}}}

is not defined at

x = - 1

, therefore:

x = - \frac{3}{5}, x = \frac{3}{5}

What is the critical (8x^2-24x)/(3(x+1)^{1/3)} ?
The critical (8x^2-24x)/(3(x+1)^{1/3)} is x=-3/(sqrt(5)),x= 3/(sqrt(5))