What is the asymptotes of f(x)=(-6x^2-7x+1)/(2x+3) ?

The asymptotes of f(x)=(-6x^2-7x+1)/(2x+3) is Vertical: x=-3/2 ,Slant: y=-3x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(-6x^2-7x+1)/(2x+3)

asymptotes

f (x) = \frac{- 6 x ^{2} - 7 x + 1}{2 x + 3}

Vertical : x = - \frac{3}{2}, Slant : y = - 3 x + 1

Solution steps

Vertical asymptotes of

\frac{- 6 x ^{2} - 7 x + 1}{2 x + 3} : x = - \frac{3}{2}

Horizontal Asymptotes of

\frac{- 6 x ^{2} - 7 x + 1}{2 x + 3} :

None

Slant Asymptotes of

\frac{- 6 x ^{2} - 7 x + 1}{2 x + 3} : y = - 3 x + 1

Vertical : x = - \frac{3}{2}, Slant : y = - 3 x + 1

f (x) = 2^{x} + 1

f (x) = \frac{x}{ln ( x )}

\frac{4}{t ^{2} - 9}

f (x) = 5 x^{4} - 3

f (x) = - (x - 5)^{2} - 9

What is the asymptotes of f(x)=(-6x^2-7x+1)/(2x+3) ?
The asymptotes of f(x)=(-6x^2-7x+1)/(2x+3) is Vertical: x=-3/2 ,Slant: y=-3x+1