What is the perpendicular 3x+6y=12,(3,3) ?

The perpendicular 3x+6y=12,(3,3) is y=2x-3

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perpendicular 3x+6y=12,(3,3)

perpendicular

3 x + 6 y = 12, (3, 3)

y = 2 x - 3

Solution steps

Find the line

y = mx + b

perpendicular to

3 x + 6 y = 12

that passes through

(3, 3)

Find the slope of

3 x + 6 y = 12 : m = - \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = 2

Find the line with slope m=

2

and passing through

(3, 3) : y = 2 x - 3

y = 2 x - 3

x^{2} - 3 x + 3

x^{3} + 7

f (x) = \frac{- 3 x}{2 x + 7}

x^{2} 5 + x

tan (2 x) cos (x)

What is the perpendicular 3x+6y=12,(3,3) ?
The perpendicular 3x+6y=12,(3,3) is y=2x-3