What is the critical (x^2)/((x-2)^3) ?

The critical (x^2)/((x-2)^3) is x=-4,x=0

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critical (x^2)/((x-2)^3)

critical points

\frac{x ^{2}}{( x - 2 ) ^{3}}

x = - 4, x = 0

Solution steps

\frac{x ^{2}}{( x - 2 ) ^{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{( x - 2 ) ^{3}} : x < 2 or x > 2

\frac{x ^{2}}{( x - 2 ) ^{3}}

is not defined at

x = 2

, therefore:

x = - 4, x = 0