What is the critical f(x)=(x^2)/(3x-6) ?

The critical f(x)=(x^2)/(3x-6) is x=0,x=4

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critical f(x)=(x^2)/(3x-6)

critical points

f (x) = \frac{x ^{2}}{3 x - 6}

x = 0, x = 4

Solution steps

\frac{x ^{2}}{3 x - 6}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{3 x - 6} : x < 2 or x > 2

\frac{x ^{2}}{3 x - 6}

is not defined at

x = 2

, therefore:

x = 0, x = 4

What is the critical f(x)=(x^2)/(3x-6) ?
The critical f(x)=(x^2)/(3x-6) is x=0,x=4