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Popular >

range of f(x)=-x^2-5

Solution

range

f (x) = - x^{2} - 5

Solution

f (x) \leq - 5

+1

Interval Notation

(- \infty, - 5]

Solution steps

Vertex of

- x^{2} - 5 :

Maximum

(0, - 5)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, - 5)

f (x) \leq - 5

Popular Examples

domain of (1-9sqrt(x))/x domain

\frac{1 - 9 x}{x}

intercepts of y=2(x-b)^2 intercepts

y = 2 (x - b)^{2}

critical y=x^2-5x critical points

y = x^{2} - 5 x

shift y=6cos(3x+pi/2)shift

y = 6 cos (3 x + \frac{π}{2})

domain of f(x)=(6x+7)/(2x-9)domain

f (x) = \frac{6 x + 7}{2 x - 9}

Frequently Asked Questions (FAQ)

What is the range of f(x)=-x^2-5 ?
The range of f(x)=-x^2-5 is f(x)<=-5