What is the domain of f(x)=sqrt(4-x^2)-sqrt(x+1) ?

The domain of f(x)=sqrt(4-x^2)-sqrt(x+1) is -1<= x<= 2

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domain of f(x)=sqrt(4-x^2)-sqrt(x+1)

domain

f (x) = 4 - x^{2} - x + 1

- 1 \leq x \leq 2

Interval Notation

[- 1, 2]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 2

The function domain

- 1 \leq x \leq 2

2 x - y = 5

f (t) = \frac{4}{t}

f (x) = \frac{x - 2}{3 x + 5}

f (x) = 6 + \frac{40}{x}

f (x) = - 5 x^{2} - 40 x - 77

What is the domain of f(x)=sqrt(4-x^2)-sqrt(x+1) ?
The domain of f(x)=sqrt(4-x^2)-sqrt(x+1) is -1<= x<= 2