What is the critical f(x)=((x^2+2))/(2x-1) ?

The critical f(x)=((x^2+2))/(2x-1) is x=-1,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

critical f(x)=((x^2+2))/(2x-1)

critical points

f (x) = \frac{( x ^{2} + 2 )}{2 x - 1}

x = - 1, x = 2

Solution steps

\frac{x ^{2} + 2}{2 x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 2, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 2}{2 x - 1} : x < \frac{1}{2} or x > \frac{1}{2}

\frac{x ^{2} + 2}{2 x - 1}

is not defined at

x = \frac{1}{2}

, therefore:

x = - 1, x = 2

What is the critical f(x)=((x^2+2))/(2x-1) ?
The critical f(x)=((x^2+2))/(2x-1) is x=-1,x=2