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Popular >

shift 2sin(2x)+3

Solution

shift

2 sin (2 x) + 3

Solution

Phase : 0, Vertical : 3

Solution steps

f (x) = 2 sin (2 x) + 3

g (B x - C) = sin (2 x), B = 2, C = 0, D = 3

Therefore, the phase shift

\frac{C}{B}

is

\frac{0}{2}

0

The vertical shift

D

is

3

3

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inverse of f(x)=-1/(3-x)-2 inverse

f (x) = - \frac{1}{3 - x} - 2

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f (x) = \frac{2 x + 1}{4 - x}

inflection y=x^3-3x+7 inflection points

y = x^{3} - 3 x + 7

range of (x-8)/(2x^2)range

\frac{x - 8}{2 x ^{2}}

Frequently Asked Questions (FAQ)

What is the shift 2sin(2x)+3 ?
The shift 2sin(2x)+3 is Phase:0, Vertical:3