What is the critical y=x^2e^{-3x} ?

The critical y=x^2e^{-3x} is x=0,x= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical y=x^2e^{-3x}

critical points

y = x^{2} e^{- 3 x}

x = 0, x = \frac{2}{3}

Solution steps

x^{2} e^{- 3 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{2}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{2} e^{- 3 x} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{2}{3}

f (x) = \frac{11}{\frac{6}{x} - 1}

f (x) = - 8

f (x) = ln (e^{x} - 7)

\frac{x ^{2} - 16}{6 x ^{2}}

ln (13 x + 4)