What is the critical f(x)=(2-x^2)/(3x^2-1) ?

The critical f(x)=(2-x^2)/(3x^2-1) is x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

critical f(x)=(2-x^2)/(3x^2-1)

critical points

f (x) = \frac{2 - x ^{2}}{3 x ^{2} - 1}

x = 0

Solution steps

\frac{2 - x ^{2}}{3 x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - \frac{1}{3}, x = \frac{1}{3}

Identify critical points not in

f (x)

domain

Domain of

\frac{2 - x ^{2}}{3 x ^{2} - 1} : x < - \frac{1}{3} or - \frac{1}{3} < x < \frac{1}{3} or x > \frac{1}{3}

\frac{2 - x ^{2}}{3 x ^{2} - 1}

is not defined at

x = - \frac{1}{3}, x = \frac{1}{3}

, therefore:

x = 0

What is the critical f(x)=(2-x^2)/(3x^2-1) ?
The critical f(x)=(2-x^2)/(3x^2-1) is x=0