What is the critical f(x)=((x^2+1))/(2x) ?

The critical f(x)=((x^2+1))/(2x) is x=-1,x=1

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critical f(x)=((x^2+1))/(2x)

critical points

f (x) = \frac{( x ^{2} + 1 )}{2 x}

x = - 1, x = 1

Solution steps

\frac{x ^{2} + 1}{2 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 1}{2 x} : x < 0 or x > 0

\frac{x ^{2} + 1}{2 x}

is not defined at

x = 0

, therefore:

x = - 1, x = 1

What is the critical f(x)=((x^2+1))/(2x) ?
The critical f(x)=((x^2+1))/(2x) is x=-1,x=1