What is the inflection (x^2-4)^2 ?

The inflection (x^2-4)^2 is (-2/(sqrt(3)), 64/9),(2/(sqrt(3)), 64/9)

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inflection (x^2-4)^2

inflection points

(x^{2} - 4)^{2}

(- \frac{2}{3}, \frac{64}{9}), (\frac{2}{3}, \frac{64}{9})

Solution steps

f^{''} (x) = 4 (3 x^{2} - 4)

Find intervals:

Concave Upward

: - \infty < x < - \frac{2}{3},

Concave Downward

: - \frac{2}{3} < x < \frac{2}{3},

Concave Upward

: \frac{2}{3} < x < \infty

Plug

x = - \frac{2}{3}

into

(x^{2} - 4)^{2} : \frac{64}{9}

(- \frac{2}{3}, \frac{64}{9})

Plug

x = \frac{2}{3}

into

(x^{2} - 4)^{2} : \frac{64}{9}

(\frac{2}{3}, \frac{64}{9})

(- \frac{2}{3}, \frac{64}{9}), (\frac{2}{3}, \frac{64}{9})

f (x) = g (x) = - 0.5 x

f (x) = \frac{x ^{2} - x - 2}{x ^{2} + x - 6}

f (x) = 4 x^{5}

f (x) = 2 x

What is the inflection (x^2-4)^2 ?
The inflection (x^2-4)^2 is (-2/(sqrt(3)), 64/9),(2/(sqrt(3)), 64/9)