What is the critical 5x^2ln(x) ?

The critical 5x^2ln(x) is x= 1/(sqrt(e))

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critical 5x^2ln(x)

critical points

5 x^{2} ln (x)

x = \frac{1}{e}

Solution steps

5 x^{2} ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

5 x^{2} ln (x) : x > 0

5 x^{2} ln (x)

is not defined at

x = 0

, therefore:

x = \frac{1}{e}