What is the critical (x^2-2x+2)/(x-1) ?

The critical (x^2-2x+2)/(x-1) is x=0,x=2

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critical (x^2-2x+2)/(x-1)

critical points

\frac{x ^{2} - 2 x + 2}{x - 1}

x = 0, x = 2

Solution steps

\frac{x ^{2} - 2 x + 2}{x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 2 x + 2}{x - 1} : x < 1 or x > 1

\frac{x ^{2} - 2 x + 2}{x - 1}

is not defined at

x = 1

, therefore:

x = 0, x = 2

What is the critical (x^2-2x+2)/(x-1) ?
The critical (x^2-2x+2)/(x-1) is x=0,x=2