What is the critical f(x)=x^{1/7}-x^{-6/7} ?

The critical f(x)=x^{1/7}-x^{-6/7} is x=-6

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critical f(x)=x^{1/7}-x^{-6/7}

critical points

f (x) = x^{\frac{1}{7}} - x^{- \frac{6}{7}}

x = - 6

Solution steps

x^{\frac{1}{7}} - x^{- \frac{6}{7}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 6, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{1}{7}} - x^{- \frac{6}{7}} : x < 0 or x > 0

x^{\frac{1}{7}} - x^{- \frac{6}{7}}

is not defined at

x = 0

, therefore:

x = - 6

What is the critical f(x)=x^{1/7}-x^{-6/7} ?
The critical f(x)=x^{1/7}-x^{-6/7} is x=-6