What is the inverse of f(x)=-2x^2-1 ?

The inverse of f(x)=-2x^2-1 is sqrt(-(x+1)/2),-sqrt(-(x+1)/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=-2x^2-1

inverse

f (x) = - 2 x^{2} - 1

- \frac{x + 1}{2}, - - \frac{x + 1}{2}

Solution steps

y = - 2 x^{2} - 1

Replace

x

with

y

x = - 2 y^{2} - 1

Solve for

y, x = - 2 y^{2} - 1

- \frac{x + 1}{2}, - - \frac{x + 1}{2}

(- 5, 3), (10, 0)

lo g_{2} (2 - x)

\frac{8}{\frac{7}{x - 4}}

2^{x + 3}

f (x) = \frac{x + 9}{x ^{2} + 2 x}

What is the inverse of f(x)=-2x^2-1 ?
The inverse of f(x)=-2x^2-1 is sqrt(-(x+1)/2),-sqrt(-(x+1)/2)