What is the critical f(x)=8x^2ln(x) ?

The critical f(x)=8x^2ln(x) is x= 1/(sqrt(e))

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critical f(x)=8x^2ln(x)

critical points

f (x) = 8 x^{2} ln (x)

x = \frac{1}{e}

Solution steps

8 x^{2} ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

8 x^{2} ln (x) : x > 0

8 x^{2} ln (x)

is not defined at

x = 0

, therefore:

x = \frac{1}{e}

What is the critical f(x)=8x^2ln(x) ?
The critical f(x)=8x^2ln(x) is x= 1/(sqrt(e))