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Popular >

range of f(x)=x^2-2x-8

Solution

range

f (x) = x^{2} - 2 x - 8

Solution

f (x) \geq - 9

+1

Interval Notation

[- 9, \infty)

Solution steps

Vertex of

x^{2} - 2 x - 8 :

Minimum

(1, - 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (1, - 9)

f (x) \geq - 9

Popular Examples

asymptotes of (x+1)/((x-3)^2)asymptotes

\frac{x + 1}{( x - 3 ) ^{2}}

critical f(x)=3y^4-12y^2 critical points

f (x) = 3 y^{4} - 12 y^{2}

inverse of f(x)=(sqrt(7y+637))/7-3 inverse

f (x) = \frac{7 y + 637}{7} - 3

intercepts of f(x)=(0.33)^x intercepts

f (x) = (0.33)^{x}

inverse of f(x)=e^{2x}+1 inverse

f (x) = e^{2 x} + 1

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2-2x-8 ?
The range of f(x)=x^2-2x-8 is f(x)>=-9