What is the domain of f(x)=sqrt(x^2+x-12) ?

The domain of f(x)=sqrt(x^2+x-12) is x = 3

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domain of f(x)=sqrt(x^2+x-12)

domain

f (x) = x^{2} + x - 12

x \leq - 4 or x \geq 3

Interval Notation

(- \infty, - 4] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 3

The function domain

x \leq - 4 or x \geq 3

f (x) = 2 x + 7

f (x) = x^{3} - x^{2} - 9 x + 9

f (x) = \frac{5 x ^{3} - 9}{x ^{3} + 13 x ^{2} + 42 x}

f (x) = 4^{x}

(8, - 5), (4, 3)

What is the domain of f(x)=sqrt(x^2+x-12) ?
The domain of f(x)=sqrt(x^2+x-12) is x<=-4\lor x>= 3