What is the extreme f(x)=4x^3-6x^2-72x+30 ?

The extreme f(x)=4x^3-6x^2-72x+30 is Maximum(-2,118),Minimum(3,-132)

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extreme f(x)=4x^3-6x^2-72x+30

extreme points

f (x) = 4 x^{3} - 6 x^{2} - 72 x + 30

Maximum (- 2, 118), Minimum (3, - 132)

Solution steps

f^{'} (x) = 12 x^{2} - 12 x - 72

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 2

into

4 x^{3} - 6 x^{2} - 72 x + 30 : 118

Maximum (- 2, 118)

Plug

x = 3

into

4 x^{3} - 6 x^{2} - 72 x + 30 : - 132

Minimum (3, - 132)

Maximum (- 2, 118), Minimum (3, - 132)

What is the extreme f(x)=4x^3-6x^2-72x+30 ?
The extreme f(x)=4x^3-6x^2-72x+30 is Maximum(-2,118),Minimum(3,-132)