What is the extreme f(x)=x^3-(3x^2)/2 ?

The extreme f(x)=x^3-(3x^2)/2 is Maximum(0,0),Minimum(1,-1/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^3-(3x^2)/2

extreme points

f (x) = x^{3} - \frac{3 x ^{2}}{2}

Maximum (0, 0), Minimum (1, - \frac{1}{2})

Solution steps

f^{'} (x) = 3 x^{2} - 3 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

x^{3} - \frac{3 x ^{2}}{2} : 0

Maximum (0, 0)

Plug

x = 1

into

x^{3} - \frac{3 x ^{2}}{2} : - \frac{1}{2}

Minimum (1, - \frac{1}{2})

Maximum (0, 0), Minimum (1, - \frac{1}{2})

What is the extreme f(x)=x^3-(3x^2)/2 ?
The extreme f(x)=x^3-(3x^2)/2 is Maximum(0,0),Minimum(1,-1/2)