What is the inverse of f(x)=3-(x-1)^2 ?

The inverse of f(x)=3-(x-1)^2 is sqrt(-x+3)+1,-sqrt(-x+3)+1

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inverse of f(x)=3-(x-1)^2

inverse

f (x) = 3 - (x - 1)^{2}

- x + 3 + 1, - - x + 3 + 1

Solution steps

y = 3 - (x - 1)^{2}

Replace

x

with

y

x = 3 - (y - 1)^{2}

Solve for

y, x = 3 - (y - 1)^{2}

- x + 3 + 1, - - x + 3 + 1

f (x) = 3 x^{6} + x^{10} + 4

1 + 3 + 4 x

f (x) = 9 x^{2}, x \leq 0

f (x) = \frac{7 x ^{2} + 9 x - 10}{x ^{3}}

What is the inverse of f(x)=3-(x-1)^2 ?
The inverse of f(x)=3-(x-1)^2 is sqrt(-x+3)+1,-sqrt(-x+3)+1