What is the domain of f(x)= 1/(x-2)g(x)=sqrt(x+4) ?

The domain of f(x)= 1/(x-2)g(x)=sqrt(x+4) is x>=-4

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domain of f(x)= 1/(x-2)g(x)=sqrt(x+4)

domain

f (x) = \frac{1}{x - 2} g (x) = x + 4

x \geq - 4

Interval Notation

[- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

The function domain

x \geq - 4

f (x) = y - 3 = \frac{7}{8} (x - 4)

f (x) = - x^{3} - 6 x^{2} + 1

- 5 x - 12 y = 11

- \frac{2}{3} x - 5

\frac{5}{12 + 3 x}

What is the domain of f(x)= 1/(x-2)g(x)=sqrt(x+4) ?
The domain of f(x)= 1/(x-2)g(x)=sqrt(x+4) is x>=-4