What is the extreme f(x)=x^3+6x^2+9x-8 ?

The extreme f(x)=x^3+6x^2+9x-8 is Maximum(-3,-8),Minimum(-1,-12)

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extreme f(x)=x^3+6x^2+9x-8

extreme points

f (x) = x^{3} + 6 x^{2} + 9 x - 8

Maximum (- 3, - 8), Minimum (- 1, - 12)

Solution steps

f^{'} (x) = 3 x^{2} + 12 x + 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 3

into

x^{3} + 6 x^{2} + 9 x - 8 : - 8

Maximum (- 3, - 8)

Plug

x = - 1

into

x^{3} + 6 x^{2} + 9 x - 8 : - 12

Minimum (- 1, - 12)

Maximum (- 3, - 8), Minimum (- 1, - 12)

What is the extreme f(x)=x^3+6x^2+9x-8 ?
The extreme f(x)=x^3+6x^2+9x-8 is Maximum(-3,-8),Minimum(-1,-12)