What is the extreme f(x,y)=x^2+y^2+xy-2x-y+1 ?

The extreme f(x,y)=x^2+y^2+xy-2x-y+1 is Minimum(1,0)

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extreme f(x,y)=x^2+y^2+xy-2x-y+1

extreme points

f (x, y) = x^{2} + y^{2} + x y - 2 x - y + 1

Minimum (1, 0)

Solution steps

Find the critical points:

(1, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(1, 0) :

Minimum

Minimum (1, 0)

What is the extreme f(x,y)=x^2+y^2+xy-2x-y+1 ?
The extreme f(x,y)=x^2+y^2+xy-2x-y+1 is Minimum(1,0)