What is the extreme f(-infinity ,infinity)=(x-2)^2+1 ?

The extreme f(-infinity ,infinity)=(x-2)^2+1 is Minimum(2,1)

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extreme f(-infinity ,infinity)=(x-2)^2+1

extreme points

f (- \infty, \infty) = (x - 2)^{2} + 1

Minimum (2, 1)

Solution steps

f^{'} (x) = 2 x - 4

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

(x - 2)^{2} + 1 : 1

Minimum (2, 1)

What is the extreme f(-infinity ,infinity)=(x-2)^2+1 ?
The extreme f(-infinity ,infinity)=(x-2)^2+1 is Minimum(2,1)