What is the extreme f(x)=sin(x),0<= x< pi/2 ?

The extreme f(x)=sin(x),0<= x< pi/2 is Minimum(0,0)

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extreme f(x)=sin(x),0<= x< pi/2

extreme points

f (x) = sin (x), 0 \leq x < \frac{π}{2}

Minimum (0, 0)

Solution steps

Find the critical points:

x = 0

Domain of

sin (x), 0 \leq x < \frac{π}{2} : 0 \leq x < \frac{π}{2}

Find intervals:

Increasing

: 0 < x < \frac{π}{2}

Plug the extreme point

x = 0

into

sin (x) \Rightarrow y = 0

Minimum (0, 0)

What is the extreme f(x)=sin(x),0<= x< pi/2 ?
The extreme f(x)=sin(x),0<= x< pi/2 is Minimum(0,0)