What is the perpendicular y= 7/5 x+6,(2,-6) ?

The perpendicular y= 7/5 x+6,(2,-6) is y=-5/7 x-32/7

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perpendicular y= 7/5 x+6,(2,-6)

perpendicular

y = \frac{7}{5} x + 6, (2, - 6)

y = - \frac{5}{7} x - \frac{32}{7}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{7}{5} x + 6

that passes through

(2, - 6)

Find the slope of

y = \frac{7}{5} x + 6 : m = \frac{7}{5}

Compute the slope of the perpendicular line:

m_{p} = - \frac{5}{7}

Find the line with slope m=

- \frac{5}{7}

and passing through

(2, - 6) : y = - \frac{5}{7} x - \frac{32}{7}

y = - \frac{5}{7} x - \frac{32}{7}

f (x) = (8 (\frac{7}{8}) - 7)^{2} = 23

f (x) = x^{3} - 3 x^{2} + 3 x + 1

f (x) = x ln (3 x)

\frac{x ^{3} - 16 x}{- 3 x ^{2} + 3 x + 18}

f (x) = x^{4} + 8 x^{2} + 16

What is the perpendicular y= 7/5 x+6,(2,-6) ?
The perpendicular y= 7/5 x+6,(2,-6) is y=-5/7 x-32/7