What is the extreme f(x,y)=-11*y^2+(x+16)^2+1 ?

The extreme f(x,y)=-11*y^2+(x+16)^2+1 is Saddle(-16,0)

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extreme f(x,y)=-11*y^2+(x+16)^2+1

extreme points

f (x, y) = - 11 \cdot y^{2} + (x + 16)^{2} + 1

Saddle (- 16, 0)

Solution steps

Find the critical points:

(- 16, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 22

D (x, y) = - 44

Check the sign of at each critical point

Check critical point

(- 16, 0) :

Saddle

Saddle (- 16, 0)

What is the extreme f(x,y)=-11*y^2+(x+16)^2+1 ?
The extreme f(x,y)=-11*y^2+(x+16)^2+1 is Saddle(-16,0)