extreme f(x)=-x^3-9x^2

Lösung

extrempunkte

f (x) = - x^{3} - 9 x^{2}

Minimum (- 6, - 108), Maximum (0, 0)

Schritte zur Lösung

f^{'} (x) = - 3 x^{2} - 18 x

Intervalle finden:

Absteigend

: - \infty < x < - 6,

Ansteigend

: - 6 < x < 0,

Absteigend

: 0 < x < \infty

Stecke

x = - 6

- x^{3} - 9 x^{2} : - 108

Minimum (- 6, - 108)

Stecke

x = 0

- x^{3} - 9 x^{2} : 0

Maximum (0, 0)

Minimum (- 6, - 108), Maximum (0, 0)

e x t re m e f (x) = 3 sin^{2} (x)

e x t re m e f (x) = 12 cos (x) + 6 sin (2 x)

e x t re m e U (x, y) = ln (x^{2} + 4 y^{2} - 1)

e x t re m e f (x) = \frac{x ^{2} + 2 x - 7}{x ^{2} + 2 x - 3}

e x t re m e f (x, y) = y x e^{- (x^{2} + y^{2})}