What is the extreme f(x,y)=x^2+xy+y^2-34y+385 ?

The extreme f(x,y)=x^2+xy+y^2-34y+385 is Minimum(-34/3 , 68/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x,y)=x^2+xy+y^2-34y+385

extreme points

f (x, y) = x^{2} + x y + y^{2} - 34 y + 385

Minimum (- \frac{34}{3}, \frac{68}{3})

Solution steps

Find the critical points:

(- \frac{34}{3}, \frac{68}{3})

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(- \frac{34}{3}, \frac{68}{3}) :

Minimum

Minimum (- \frac{34}{3}, \frac{68}{3})

What is the extreme f(x,y)=x^2+xy+y^2-34y+385 ?
The extreme f(x,y)=x^2+xy+y^2-34y+385 is Minimum(-34/3 , 68/3)