What is the extreme f(x)=x^3-6x ?

The extreme f(x)=x^3-6x is Maximum(-sqrt(2),4sqrt(2)),Minimum(sqrt(2),-4sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^3-6x

extreme points

f (x) = x^{3} - 6 x

Maximum (- 2, 42), Minimum (2, - 42)

Solution steps

f^{'} (x) = 3 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 6 x : 42

Maximum (- 2, 42)

Plug

x = 2

into

x^{3} - 6 x : - 42

Minimum (2, - 42)

Maximum (- 2, 42), Minimum (2, - 42)

What is the extreme f(x)=x^3-6x ?
The extreme f(x)=x^3-6x is Maximum(-sqrt(2),4sqrt(2)),Minimum(sqrt(2),-4sqrt(2))