extreme f(x)=3(x^2+4)(x^2+8)^2

Lösung

extrempunkte

f (x) = 3 (x^{2} + 4) (x^{2} + 8)^{2}

Minimum (0, 768)

Schritte zur Lösung

f^{'} (x) = 3 (6 x^{5} + 80 x^{3} + 256 x)

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = 0

3 (x^{2} + 4) (x^{2} + 8)^{2} : 768

Minimum (0, 768)

e x t re m e f (x) = \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + 1

e x t re m e f (x, y) = \frac{1}{3} x^{2} + 2 x y + 3 y^{2} + 4 x - 1

e x t re m e f (x, y) = 4 x + 6 y - x^{2} - y^{2} + 8

e x t re m e f (x) = 2 e^{x} - e^{x^{2}}

e x t re m e f (x) = \frac{4 x - 12}{( x - 2 ) ^{2}}