What is the inverse of f(x)= 1/6 x^2-1 ?

The inverse of f(x)= 1/6 x^2-1 is sqrt(6x+6),-sqrt(6x+6)

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inverse of f(x)= 1/6 x^2-1

inverse

f (x) = \frac{1}{6} x^{2} - 1

6 x + 6, - 6 x + 6

Solution steps

y = \frac{1}{6} x^{2} - 1

Replace

x

with

y

x = \frac{1}{6} y^{2} - 1

Solve for

y, x = \frac{1}{6} y^{2} - 1

6 x + 6, - 6 x + 6

\frac{14 x}{x + 14}

\frac{2 x - 4}{x ^{2} + x - 2}

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 5

f (x) = 5 x^{3} - 9

y = \frac{1}{5} x + \frac{4}{5}, (1, 1)

What is the inverse of f(x)= 1/6 x^2-1 ?
The inverse of f(x)= 1/6 x^2-1 is sqrt(6x+6),-sqrt(6x+6)