What is the extreme f(x)=3x^3+45x^2+81x+40 ?

The extreme f(x)=3x^3+45x^2+81x+40 is Maximum(-9,769),Minimum(-1,1)

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extreme f(x)=3x^3+45x^2+81x+40

extreme points

f (x) = 3 x^{3} + 45 x^{2} + 81 x + 40

Maximum (- 9, 769), Minimum (- 1, 1)

Solution steps

f^{'} (x) = 9 x^{2} + 90 x + 81

Find intervals:

Increasing

: - \infty < x < - 9,

Decreasing

: - 9 < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 9

into

3 x^{3} + 45 x^{2} + 81 x + 40 : 769

Maximum (- 9, 769)

Plug

x = - 1

into

3 x^{3} + 45 x^{2} + 81 x + 40 : 1

Minimum (- 1, 1)

Maximum (- 9, 769), Minimum (- 1, 1)

f (x) = - 2 x - 2 + 4

f (x) = - 6 sin (3 π x + 4) - 2

f (x) = 6 x^{2} + 6 x - 1

f (x) = \frac{1}{( x + 1 ) ^{2}}

f (x) = 11 - x

What is the extreme f(x)=3x^3+45x^2+81x+40 ?
The extreme f(x)=3x^3+45x^2+81x+40 is Maximum(-9,769),Minimum(-1,1)