What is the inverse of sqrt(16-x^2) ?

The inverse of sqrt(16-x^2) is sqrt(-x^2+16),-sqrt(-x^2+16)

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inverse of sqrt(16-x^2)

inverse

16 - x^{2}

- x^{2} + 16, - - x^{2} + 16

Solution steps

y = 16 - x^{2}

Replace

x

with

y

x = 16 - y^{2}

Solve for

y, x = 16 - y^{2}

- x^{2} + 16, - - x^{2} + 16

f (x) = 4 x - 16

\frac{x + 2}{x ^{2} + 3 x - 10}

x^{2} + 2 x - 3

f (x) = - x^{2} - 5

f (x) = 7 x + 5

What is the inverse of sqrt(16-x^2) ?
The inverse of sqrt(16-x^2) is sqrt(-x^2+16),-sqrt(-x^2+16)