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Popular Functions >

range of-x^2+36

Solution

range

Solution

f (x) \leq 36

+1

Interval Notation

Solution steps

Vertex of

- x^{2} + 36 :

Maximum

(0, 36)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (0, 36)

f (x) \leq 36

Graph

Popular Examples

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symmetry y=x^5+6x

asymptotes of f(x)=(4x)/(x^2-16)

slope ofintercept 7x-y=-9

extreme f(x)=5x^2+8x-9

Frequently Asked Questions (FAQ)

What is the range of-x^2+36 ?
The range of-x^2+36 is f(x)<= 36