What is the perpendicular y=-5x+2,(1,-3) ?

The perpendicular y=-5x+2,(1,-3) is y= 1/5 x-16/5

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perpendicular y=-5x+2,(1,-3)

perpendicular

y = - 5 x + 2, (1, - 3)

y = \frac{1}{5} x - \frac{16}{5}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 5 x + 2

that passes through

(1, - 3)

Find the slope of

y = - 5 x + 2 : m = - 5

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{5}

Find the line with slope m=

\frac{1}{5}

and passing through

(1, - 3) : y = \frac{1}{5} x - \frac{16}{5}

y = \frac{1}{5} x - \frac{16}{5}

f (x) = (x + 2)^{2} - 3

f (x) = \frac{( 4 )}{( x - 2 ) ^{2}}

y + 1 = 6 (x - 3)

f (x) = - (x + 3)^{2} + 1

f (x) = 3 π^{5}

What is the perpendicular y=-5x+2,(1,-3) ?
The perpendicular y=-5x+2,(1,-3) is y= 1/5 x-16/5