extreme f(x)=x^3+10x^2+8

Lösung

extrempunkte

f (x) = x^{3} + 10 x^{2} + 8

Maximum (- \frac{20}{3}, \frac{4216}{27}), Minimum (0, 8)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} + 20 x

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{20}{3},

Absteigend

: - \frac{20}{3} < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = - \frac{20}{3}

x^{3} + 10 x^{2} + 8 : \frac{4216}{27}

Maximum (- \frac{20}{3}, \frac{4216}{27})

Stecke

x = 0

x^{3} + 10 x^{2} + 8 : 8

Minimum (0, 8)

Maximum (- \frac{20}{3}, \frac{4216}{27}), Minimum (0, 8)

e x t re m e f (x, y) = - 6 x^{2} + 5 x y - y^{2} + x + y

e x t re m e f (x, y) = 3 x^{2} y - y^{2} + 5 x y^{2}

e x t re m e f (x) = 2 x + cos (x)

e x t re m e f (x, y) = x^{3} + x y + y^{2}

e x t re m e f (x) = - x^{4} + 4 x^{2}