What is the extreme f(x,y)=xy-4x-4y-x^2-y^2 ?

The extreme f(x,y)=xy-4x-4y-x^2-y^2 is Maximum(-4,-4)

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extreme f(x,y)=xy-4x-4y-x^2-y^2

extreme points

f (x, y) = x y - 4 x - 4 y - x^{2} - y^{2}

Maximum (- 4, - 4)

Solution steps

Find the critical points:

(- 4, - 4)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(- 4, - 4) :

Maximum

Maximum (- 4, - 4)

What is the extreme f(x,y)=xy-4x-4y-x^2-y^2 ?
The extreme f(x,y)=xy-4x-4y-x^2-y^2 is Maximum(-4,-4)