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Popular Functions >

extreme (2x^2+5)/(x^2-25)

Solution

extreme points

\frac{2 x ^{2} + 5}{x ^{2} - 25}

Solution

Maximum (0, - \frac{1}{5})

Solution steps

f^{'} (x) = - \frac{110 x}{( x ^{2} - 25 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = 0

into

\frac{2 x ^{2} + 5}{x ^{2} - 25} : - \frac{1}{5}

Maximum (0, - \frac{1}{5})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme (2x^2+5)/(x^2-25) ?
The extreme (2x^2+5)/(x^2-25) is Maximum(0,-1/5)