extreme f(x)=(x-2)^4

Lösung

extrempunkte

f (x) = (x - 2)^{4}

Minimum (2, 0)

Schritte zur Lösung

f^{'} (x) = 4 (x - 2)^{3}

Intervalle finden:

Absteigend

: - \infty < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = 2

(x - 2)^{4} : 0

Minimum (2, 0)

e x t re m e f (x) = 8 x^{3} - 17 x^{2} + 12 x + 14

e x t re m e f (x, y) = 3 y^{3} + 7 x y - 9 x^{2} - 5

e x t re m e f (x) = - \frac{cos ( 2 x )}{2} - 2 sin (x)

e x t re m e f (x) = e^{x^{2} - 4 x - 1}

e x t re m e y = e^{x} + I n x - x^{2} + \frac{3}{x ^{5}} + 3