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Popular Functions >

extreme f(x)=-2x^2+3x+7

Solution

extreme points

f (x) = - 2 x^{2} + 3 x + 7

Solution

Maximum (\frac{3}{4}, \frac{65}{8})

Solution steps

f^{'} (x) = - 4 x + 3

Find intervals:

Increasing

: - \infty < x < \frac{3}{4},

Decreasing

: \frac{3}{4} < x < \infty

Plug

x = \frac{3}{4}

into

- 2 x^{2} + 3 x + 7 : \frac{65}{8}

Maximum (\frac{3}{4}, \frac{65}{8})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^2+3x+7 ?
The extreme f(x)=-2x^2+3x+7 is Maximum(3/4 , 65/8)