What is the extreme f(x)=x^4-2x^2-3 ?

The extreme f(x)=x^4-2x^2-3 is Minimum(-1,-4),Maximum(0,-3),Minimum(1,-4)

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extreme f(x)=x^4-2x^2-3

extreme points

f (x) = x^{4} - 2 x^{2} - 3

Minimum (- 1, - 4), Maximum (0, - 3), Minimum (1, - 4)

Solution steps

f^{'} (x) = 4 x^{3} - 4 x

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{4} - 2 x^{2} - 3 : - 4

Minimum (- 1, - 4)

Plug

x = 0

into

x^{4} - 2 x^{2} - 3 : - 3

Maximum (0, - 3)

Plug

x = 1

into

x^{4} - 2 x^{2} - 3 : - 4

Minimum (1, - 4)

Minimum (- 1, - 4), Maximum (0, - 3), Minimum (1, - 4)

What is the extreme f(x)=x^4-2x^2-3 ?
The extreme f(x)=x^4-2x^2-3 is Minimum(-1,-4),Maximum(0,-3),Minimum(1,-4)