What is the critical f(x)=x^3-3x^2-9x+10 ?

The critical f(x)=x^3-3x^2-9x+10 is x=-1,x=3

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critical f(x)=x^3-3x^2-9x+10

critical points

f (x) = x^{3} - 3 x^{2} - 9 x + 10

x = - 1, x = 3

Solution steps

x^{3} - 3 x^{2} - 9 x + 10

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 3

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 3 x^{2} - 9 x + 10 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 3

y = 3 x - 7

3 x + y = 10

f (x) = \frac{4}{x + 3}

f (x) = \frac{( 6 - 2 x ^{2} )}{( x ^{2} - 16 )}

f (x) = x^{3} - 4 x

What is the critical f(x)=x^3-3x^2-9x+10 ?
The critical f(x)=x^3-3x^2-9x+10 is x=-1,x=3