What is the extreme f(x)=sqrt(x^2-1) ?

The extreme f(x)=sqrt(x^2-1) is Minimum(-1,0),Minimum(1,0)

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extreme f(x)=sqrt(x^2-1)

extreme points

f (x) = x^{2} - 1

Minimum (- 1, 0), Minimum (1, 0)

Solution steps

f^{'} (x) = \frac{x}{x ^{2} - 1}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{2} - 1 : 0

Minimum (- 1, 0)

Plug

x = 1

into

x^{2} - 1 : 0

Minimum (1, 0)

Minimum (- 1, 0), Minimum (1, 0)

What is the extreme f(x)=sqrt(x^2-1) ?
The extreme f(x)=sqrt(x^2-1) is Minimum(-1,0),Minimum(1,0)