What is the perpendicular y=1x+3,(-7,0) ?

The perpendicular y=1x+3,(-7,0) is y=-x-7

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perpendicular y=1x+3,(-7,0)

perpendicular

y = 1 x + 3, (- 7, 0)

y = - x - 7

Solution steps

Find the line

y = mx + b

perpendicular to

y = 1 x + 3

that passes through

(- 7, 0)

Find the slope of

y = 1 x + 3 : m = 1

Compute the slope of the perpendicular line:

m_{p} = - 1

Find the line with slope m=

- 1

and passing through

(- 7, 0) : y = - x - 7

y = - x - 7

f (x) = \frac{5 x + 1}{x - 2}

f (x) = \frac{- 2 x ^{2} + 4 x - 5}{x + 3}

f (x) = x^{3} - 12

e^{2 x - 9}

y = 1 + \frac{1}{e ^{x}}

What is the perpendicular y=1x+3,(-7,0) ?
The perpendicular y=1x+3,(-7,0) is y=-x-7