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Popular >

range of f(x)=3x^2-12x+16

Solution

range

f (x) = 3 x^{2} - 12 x + 16

Solution

f (x) \geq 4

+1

Interval Notation

[4, \infty)

Solution steps

Vertex of

3 x^{2} - 12 x + 16 :

Minimum

(2, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 3,

Vertex

(x_{v}, y_{v}) = (2, 4)

f (x) \geq 4

Popular Examples

asymptotes of f(x)= 2/x asymptotes

f (x) = \frac{2}{x}

extreme f(x)=-x^2-2x+8 extreme points

f (x) = - x^{2} - 2 x + 8

domain of f(x)=(sqrt(x-5))/(x-7)domain

f (x) = \frac{x - 5}{x - 7}

asymptotes of (x^2+1)/(2x^2-3x-2)asymptotes

\frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2}

slope ofintercept 14x-4y=36 slope intercept

14 x - 4 y = 36

Frequently Asked Questions (FAQ)

What is the range of f(x)=3x^2-12x+16 ?
The range of f(x)=3x^2-12x+16 is f(x)>= 4