What is the domain of f(x)=(x^2-9x-36)/(sqrt(x+16)) ?

The domain of f(x)=(x^2-9x-36)/(sqrt(x+16)) is x>-16

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domain of f(x)=(x^2-9x-36)/(sqrt(x+16))

domain

f (x) = \frac{x ^{2} - 9 x - 36}{x + 16}

x > - 16

Interval Notation

(- 16, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 16

Find undefined (singularity) points:

x = - 16

Combine real regions and undefined points for final function domain

x > - 16

What is the domain of f(x)=(x^2-9x-36)/(sqrt(x+16)) ?
The domain of f(x)=(x^2-9x-36)/(sqrt(x+16)) is x>-16